Final answer:
The mass percent of hydrogen in C₁₄H₁₉NO₂ is calculated by dividing the total mass of hydrogen by the molar mass of the compound and multiplying by 100%, resulting in 8.22%.
Step-by-step explanation:
To determine the mass percent of hydrogen in C₁₄H₁₉NO₂, we first need to calculate the molar mass of the compound. We use the atomic masses of carbon (C, approximately 12.01 amu), hydrogen (H, approximately 1.01 amu), nitrogen (N, approximately 14.01 amu), and oxygen (O, approximately 16.00 amu).
The molar mass of the compound is calculated as follows:
(14 × 12.01 amu) + (19 × 1.01 amu) + (14.01 amu) + (2 × 16.00 amu) = 168.14 amu + 19.19 amu + 14.01 amu + 32.00 amu = 233.34 amu.
Once we have the molar mass, we can calculate the mass percent of hydrogen by dividing the total mass of hydrogen in the formula by the molar mass of the compound and then multiplying by 100%:
(19 × 1.01 amu) / 233.34 amu × 100% = 19.19 amu / 233.34 amu × 100% = 8.22%.
Therefore, the mass percent of hydrogen in C₁₄H₁₉NO₂ is 8.22%.