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Slove for R,S 7x-22=4x+5

1 Answer

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The respective successful code execution counts for contestants R and S are R=41 and S=41.

To find the respective successful code execution counts for contestants R and S, we need to solve the equation 7x - 22 = 4x + 5 and determine the value of x. We can do this by simplifying the equation:

7x - 22 = 4x + 5

Subtracting 4x from both sides:

7x - 4x - 22 = 5

Combining like terms:

3x - 22 = 5

Adding 22 to both sides:

3x = 27

Dividing both sides by 3:

x = 9

Now that we know the value of x, we can substitute it back into the original expressions to find the respective successful code execution counts:

For contestant R: 7(9) - 22 = 63 - 22 = 41

For contestant S: 4(9) + 5 = 36 + 5 = 41

Therefore, the respective successful code execution counts for contestants R and S are R=41 and S=41.

The probable question may be:

In a technology competition, participants were tasked with solving a coding challenge. The number of successful code executions, denoted by 7x−227x−22, for contestant R, exceeded the number of successful code executions by contestant S, represented as 4x+54x+5. If the total number of code executions for both R and S combined is 412, determine the respective successful code execution counts for contestants R and S.

Additional Information:

Total Code Executions (R+SR+S) = 412

Options:

A) R=164R=164, S=248S=248

B) R=248R=248, S=164S=164

C) R=186R=186, S=226S=226

D) R=226R=226, S=186S=186

User Andrey Rubliov
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