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15 votes
15 votes
find five consecutive of integers if the um of the first three integers is 3 more than the sum of the last two.

User Benallansmith
by
2.1k points

1 Answer

20 votes
20 votes

Answer: 4,5,6,7,8

Explanation:

Let the first integer be A; then the five consecutive integers are A, A+1, A+2, A+3, and A+4.

If the sum of the first three equals the sum of the last two, then A + (A+1) + (A+2) = (A+3) + (A+4)

Combining, 3A + 3 = 2A + 7 … A =4

The five Integers are thus 4, 5, 6, 7, and 8

User Rich Bianco
by
3.3k points
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