Answer: 4,5,6,7,8
Explanation:
Let the first integer be A; then the five consecutive integers are A, A+1, A+2, A+3, and A+4.
If the sum of the first three equals the sum of the last two, then A + (A+1) + (A+2) = (A+3) + (A+4)
Combining, 3A + 3 = 2A + 7 … A =4
The five Integers are thus 4, 5, 6, 7, and 8