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How long does it take to cool off one of these magma chambers?

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Final answer:

The cooling time of a magma chamber cannot be stated precisely without specific details, but it is affected by many factors like size, thermal properties, and geothermal gradients. Simplified calculations can be made for heat transfer to satisfy energy demands or to estimate the cooling rate of lava through radiation and conduction.

Step-by-step explanation:

Understanding Magma Chamber Cooling Times

The process of cooling a magma chamber is complex and is influenced by a variety of factors, such as the chamber's size, the surrounding rock's thermal properties, and the geothermal gradient. However, a simplified consideration can be made by calculating the time required for heat to transfer out of a volume of rock assuming no heat returns from the surroundings, known as the cooling time.

Regarding the heat content at a depth of 4 km, with an ambient temperature (AT) of 100°C and a thermal energy content of 250 MJ per cubic meter of rock, let's assume we want to cool this rock down to extract thermal energy. Supposing we want to satisfy a 20 MW energy demand from this heat source, we would need to remove a significant amount of heat from a calculated volume of rock. If we extract energy at 300 MW, the time taken to cool 1.00 km³ of granite by 100°C can be estimated using the specific heat capacity of granite and the known rate of heat transfer (300 MW).

The chilling effect of Earth's surface, for example during a clear breezy night, can draw a parallel with the magma chamber cooling phenomena where radiative heat transfer plays a significant role. Earth's interior, while it cools through heat transfer to the cold outer space, is kept molten over billions of years due to the ongoing heat generation from radioactivity in the rocks. Similarly, a large volume of lava from a volcano cools both by radiation and conduction, and calculating the rate of heat transfer is essential to determine the cooling time.

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