Question

A loop of wire with resistance of 10 ohm moves in a contant non uniform magnetic field,it loses kinetic energy at a uniform rate of 4 J/s.The induce current in loop is?

a) 0
b) 2mA
c) 2.8mA
d) 20mA
e) cannot be calculated from the given data

Answer 1

The induced current in the loop is calculated using the power loss rate and the resistance of the loop, resulting in a current of 632.5 mA, which means the correct answer is not given in the options, leading to 'cannot be calculated from the given data'.

Step-by-step explanation:

The question deals with electromagnetic induction in a loop of wire moving in a magnetic field and experiencing a loss in kinetic energy which in turn is related to the electrical power in the loop. The power (P) lost as kinetic energy at a rate of 4 J/s can be matched to the electrical power dissipated in the resistance of the loop, which is given by P = I2R, where I is the induced current and R is the resistance.

By rearranging this equation, we find I = sqrt(P/R). Using the given values of P = 4 J/s and R = 10 Ω, we can calculate the current (I) as:

I = sqrt(4 W / 10 Ω)

I = sqrt(0.4 A2)

I = 0.6325 A

I = 632.5 mA

Therefore, the answer is not explicitly listed in the given options, and based on the information provided, the induced current in the loop would be 632.5 mA, which suggests that the correct answer would be option e) 'cannot be calculated from the given data' since the provided options do not include the calculated value.