Answer:
a. 1.1 m/s^2
Step-by-step explanation:
Force of Application = (60)(cos30)
= 51.96 N
Force of Friction = 30 N
Total Force = 51.96 - 30
= 21.56 N
F = ma
21.56 = 20a
a = 1.09
a = 1.1 m/s^2
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