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Rhombus PQRS with diagonals PR and QS, PQ=6x+1, QR 5-2x, and PQR+120 solve for x

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Final answer:

To solve for x in the given rhombus problem, we can use the properties of a rhombus and set up an equation based on the given information. By combining like terms and isolating x, we find that x = 1/2.

Step-by-step explanation:

To solve for x in the given problem, we need to use the properties of a rhombus and apply them to the given information. In a rhombus, the diagonals are perpendicular bisectors of each other.

Since PR and QS are diagonals of the rhombus, they are also perpendicular bisectors. Therefore, we can set up the following equation:

PQ = 6x + 1 = QR = 5 - 2x

Simplifying this equation gives us:

6x + 1 = 5 - 2x

Now, we can solve for x by combining like terms and isolating x:

6x + 2x = 5 - 1

8x = 4

x = 4/8

x = 1/2

Therefore, x = 1/2.

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