Final answer:
The work done by a 3-pound force at an angle of 60° to the horizontal in moving an object 6 feet can be calculated using the formula W = F * d * cos(θ). After converting the force and displacement to SI units, the work is found to be approximately 12.1776 Joules.
Step-by-step explanation:
To find the work done by a force, we can use the formula:
Work (W) = Force (F) x Displacement (d) x cos(θ)
Where:
- Force (F) = 3 pounds
- Displacement (d) = 6 feet
- θ (angle) = 60°
First, convert the force to Newtons by multiplying it by 4.4482 N/lb:
Force (F) = 3 pounds * 4.4482 N/lb = 13.3446 N
Next, convert the displacement to meters as the formula requires SI units:
Displacement (d) = 6 feet * 0.3048 m/ft = 1.8288 m
Now, substitute the values into the formula:
W = 13.3446 N * 1.8288 m * cos(60°)
W = 13.3446 N * 1.8288 m * 0.5
W = 12.1776 J
Therefore, the work done by the force of 3 pounds at an angle of 60° to the horizontal in moving the object 6 feet is approximately 12.1776 Joules.