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Which of the following is a solution to 2sin^2 x _ sin x - 1 = 0 a) True b) False

User Chrmod
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1 Answer

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Final answer:

The student's question relates to solving a trigonometric quadratic equation, but without the complete equation or additional context, it is not possible to provide a definite solution. General techniques to solve quadratic equations, such as factoring or the quadratic formula, would apply.

Step-by-step explanation:

The original statement provided by the student is incomplete and lacks sufficient information. However, I can provide some insight into the general concept involved. The equation presented by the student appears to be a quadratic equation in terms of sin x, which can be written as 2sin2x - sin x - 1 = 0. To solve this equation for x, we would treat it like any other quadratic equation by factoring, using the quadratic formula, or completing the square.

For example, if we were to factor this equation, we would look for two numbers that multiply to give -2 (from multiplying 2 by -1) and add to give -1 (the coefficient of sin x). However, without knowing the specifics of the factoring, it's impossible to accurately provide the solution. Nevertheless, we can say that the equation is solvable using standard algebraic techniques for solving quadratic equations.

Additionally, understanding trigonometric identities is crucial when dealing with equations involving sine and cosine, but those identities do not directly help in factoring or simplifying the quadratic equation presented.

User Rickygrimes
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