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What is the volume percentage of a solution prepared from 60 ml of methanol in 800 ml of water?

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Final answer:

The volume percentage of methanol in the solution is calculated by the formula (Volume of methanol / Total volume of solution) x 100%, which gives approximately 6.98% for a solution of 60 ml methanol in 800 ml water.

Step-by-step explanation:

The volume percentage of a solution is calculated by dividing the volume of the solute by the volume of the solution and then multiplying by 100%. In the given problem, you have 60 ml of methanol and 800 ml of water. The total volume of the solution is the sum of the volume of methanol and the volume of water, which is 60 ml + 800 ml = 860 ml.

To find the volume percentage of methanol in the solution, the calculation is as follows:

Volume percentage = (Volume of methanol / Total volume of solution) x 100%

Volume percentage = (60 ml / 860 ml) x 100%

Volume percentage = 6.98%

Therefore, the volume percentage of methanol in the solution is approximately 6.98%.

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