Question

Help please!!Which of the following best describes the technique used to graph the equation y = 9x+4 using the slope and y-intercept?

A) Mark a point at 4 on the y-axis, go down 9 and right one and mark this point.
B) Mark a point at 9 on the y-axis, go up 4 and right one and mark this point
C) Mark a point at 9 on the y-axis, go up 4 and left one and mark this point.
D) Mark a point at 4 on the y-axis, go up 9 and right one and mark this point​

Answer 1

To graph the equation y = 9x + 4, mark a point at 4 on the y-axis, then from this point go up 9 units and right 1 unit, and place another point. Connect these points to represent the line. The correct option is D.

Step-by-step explanation:

When graphing the equation y = 9x + 4 using the slope and y-intercept, you would first identify the y-intercept and the slope from the equation. The y-intercept is the value where the line crosses the y-axis when x is zero, which in this case is 4.

This is the 'b' term in the equation, which is +4. Therefore, you would start by marking a point at 4 on the y-axis. The slope, represented as 'm' in the slope-intercept form y = mx + b, is 9 in this case. This means that for every increase of 1 unit in x, y increases by 9 units.

To represent this on the graph, you would go up 9 units and right 1 unit from the initial point marked on the y-axis and place a second point. Finally, you would draw a line through these two points to represent the equation.

Therefore, the correct answer is: D) Mark a point at 4 on the y-axis, go up 9 and right one and mark this point. The correct option is D.