Line with slope 2 passing through (5,8) is y = 2x + 2.
The equation in slope-intercept form of the line that passes through the point (5,8) and has a slope of 2 is y = 2x + 2.
We can use the point-slope form of linear equations to solve this problem:
y - y1 = m(x - x1)
where m is the slope of the line and (x1, y1) is a point on the line. In this case, we know the slope is 2 and the point is (5,8).
Substituting these values into the equation, we get:
y - 8 = 2(x - 5)
Expanding the right-hand side of the equation, we get:
y - 8 = 2x - 10
Adding 8 to both sides of the equation, we get:
y = 2x - 2
Therefore, the equation in slope-intercept form of the line that passes through the point (5,8) and has a slope of 2 is y = 2x + 2.