Final answer:
To represent the cost of tennis courses at Campus A and Campus B, create a system of equations and solve for the number of hours when the costs are the same. To determine which campus to choose for a total of 10 hours, substitute h = 10 into the equations. Campus A is cost-effective when the number of hours is less than 2.
Step-by-step explanation:
To represent the cost of tennis courses at Campus A and Campus B, we can write a system of equations. Let cA be the cost at Campus A and cB be the cost at Campus B, both in dollars. Let h be the number of hours for which the courts are used. The equations are:
cA = 25h
cB = 20h + 10
To find the number of hours for which the costs are the same, we can set the two equations equal to each other and solve for h:
25h = 20h + 10
Simplifying the equation gives us:
5h = 10
Dividing both sides by 5, we get:
h = 2
Therefore, the costs are the same when 2 hours of court use are chosen.
If you want to practice for a total of 10 hours, we can substitute h = 10 into both equations to find the costs:
cA = 25(10) = 250
cB = 20(10) + 10 = 200 + 10 = 210
Therefore, if you want to practice for a total of 10 hours, it is more cost-effective to choose Campus B.
Campus A is cost-effective when the cost at Campus A is lower than the cost at Campus B. Setting up an inequality, we have:
25h < 20h + 10
Simplifying the inequality gives us:
5h < 10
Dividing both sides by 5, we get:
h < 2
Therefore, it is cost-effective to use Campus A when the number of hours is less than 2.