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27 votes
A student club plans to buy food for a soup kitchen. A case of vegetables coats $10.68. The club can spend at most $50 for this project. What are all the possible numbers of cases c that the club can buy?

User Dario Ielardi
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2 Answers

8 votes
8 votes

Final answer:

The student club can buy at most 4 cases of vegetables with their $50 budget, as buying 5 cases would exceed their budget. The possible number of cases they can buy are 0, 1, 2, 3, or 4.

Step-by-step explanation:

The question asks us to calculate the maximum number of cases of vegetables a student club can buy with a budget of $50 if each case costs $10.68.

To find out the possible number of cases c that the club can buy, you can divide the total amount of money the club can spend ($50) by the cost per case of vegetables ($10.68). This calculation gives us the following equation:

c = $50 / $10.68

Dividing $50 by $10.68 gives approximately 4.68. Since the club cannot buy a fraction of a case, they have to buy a whole number of cases. Therefore, the club can buy either 4 cases of vegetables (which would cost $42.72) and remain within their budget, or they could attempt to negotiate or find additional funds to buy the fifth case. They cannot buy 5 cases without exceeding their budget as that would cost $53.40
($10.68*5).

The student club can thus buy 0, 1, 2, 3, or 4 cases of vegetables without going over their $50 budget.

User Solarnz
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2.9k points
26 votes
26 votes

Answer:

0,1,2,3,4

Step-by-step explanation:


(50)/(16.68) = 4.68 rounded to the nearest hundredths.

User Viktor Kukurba
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2.5k points