Question

"If the mass of the helicopter, crew, and Mohinder is 8.6×105 kg. What is the upward force from air needed to lift the helicopter off the ground so that it hovers there? N

When the helicopter accelerates upwards it goes up at 4.56m/s2 What is the upward force needed to accelerate up? N

The helicopter gets the elevation it needs and it moves horizontally. What will the force from air need to be to keep it this altitude moving horizontally? N
When the helicopter gets to the hospital it descends at 3.7 m/s2 What is the upward force of air needed to allow the helicopter to descend at this rate? N"

Answer 1

To lift the helicopter off the ground and hover in place, the upward force from air needs to be equal to the weight of the helicopter, crew, and Mohinder, which is 8.44x10^6 N. When the helicopter accelerates upwards at 4.56 m/s^2, the additional upward force needed is 3.93x10^6 N. The force from air needed to keep the helicopter at a horizontal altitude depends on factors such as air resistance and the angle of the blades, and when the helicopter descends at 3.7 m/s^2, the upward force needed is 4.91x10^6 N.

Step-by-step explanation:

In order to lift the helicopter off the ground and hover in place, the upward force from air must be equal to the weight of the helicopter, crew, and Mohinder. This is calculated by multiplying the mass of the helicopter by the acceleration due to gravity, which is approximately 9.8 m/s2. So, the upward force needed to lift the helicopter off the ground is:

Force = mass * acceleration due to gravity
Force = 8.6x105 kg * 9.8 m/s2 = 8.44x106 N

When the helicopter accelerates upwards at 4.56 m/s2, it experiences an additional upward force due to the acceleration. This force is calculated using Newton's second law, which states that force is equal to mass times acceleration. So, the upward force needed to accelerate the helicopter upwards is:

Force = mass * acceleration
Force = 8.6x105 kg * 4.56 m/s2 = 3.93x106 N

Once the helicopter reaches its desired altitude and starts moving horizontally, the force from air needed to keep it at that altitude depends on factors such as air resistance and the angle of the helicopter's blades. This force is typically provided by the helicopter's engines.

When the helicopter descends at a rate of 3.7 m/s2, it experiences a downward force due to gravity. The upward force of air needed to allow the helicopter to descend at this rate is equal to the weight of the helicopter, crew, and Mohinder minus the force of gravity. This is calculated using the same formula as before:

Force = mass * acceleration due to gravity
Force = 8.6x105 kg * (9.8 m/s2 - 3.7 m/s2) = 4.91x106 N