Question

Consider the balanced chemical equation

4Al(s)+3O²(g)--> 2Al₂O₃(8)
What mole ratio should be used to calculate how many moles of oxygen gas would be needed to react completely with a given number of moles of aluminum metal? What mole ratio should be used to calculate the number of moles of product that would be expected if a given number of moles of aluminum metal reacts completely?

Answer 1

The mole ratio of aluminum to oxygen gas is 4:3. The mole ratio of aluminum to aluminum oxide is 4:2.

Step-by-step explanation:

To calculate the moles of oxygen gas needed to react completely with a given number of moles of aluminum metal, we need to use the mole ratio from the balanced chemical equation. From the equation 4Al(s) + 3O2(g) → 2Al2O3(s), the mole ratio is 4 moles of Al to 3 moles of O2. So, if you have x moles of Al, you would need (3/4)x moles of O2 to react completely.

To calculate the moles of product (Al2O3) expected when a given number of moles of aluminum metal react completely, we use the mole ratio from the balanced chemical equation. The mole ratio is 4 moles of Al to 2 moles of Al2O3. So, if you have x moles of Al, you would expect (2/4)x moles of Al2O3 to be produced.