Final answer:
To find the mass of hydrogen gas produced from 32.22 g of HCl reacting with zinc, we use stoichiometry to calculate the moles of HCl, then find the moles of H2 produced, and lastly calculate the mass of H2 using its molar mass. The resulting mass of hydrogen gas is approximately 0.89183 g.
Step-by-step explanation:
The problem asks us to determine the mass of hydrogen gas that can be produced from reacting 32.22 g of hydrochloric acid (HCl) with zinc (Zn). First, we need the molar mass of HCl, which is 36.46 grams per mole. Using stoichiometry, we can calculate how many moles of HCl this mass corresponds to by dividing the mass of HCl by its molar mass.
With the balanced chemical equation, Zn(s) + 2HCl(aq) → ZnCl₂(aq) + H₂(g), we see that 2 moles of HCl produce 1 mole of H₂. Therefore, the moles of HCl will be halved to find the moles of H₂ produced.
Calculation:
32.22 g HCl × (1 mol HCl / 36.46 g HCl) = 0.883 moles HCl
Since 2 moles of HCl produce 1 mole of H₂, the moles of H₂ will be 0.883 moles HCl / 2 = 0.4415 moles H₂.
Now, using the molar mass of H₂ (2.02 grams per mole), we can find the mass of H₂ produced:
0.4415 moles H₂ × (2.02 g H₂ / 1 mol H₂) = 0.89183 g H₂
Therefore, the mass of hydrogen gas produced from 32.22 g of HCl is approximately 0.89183 g.