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When a gas is heated to 130 °C, its volume changes from 250 mL to 375 mL. What was the temperature of the gas before it was heated?​

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Final answer:

To find the initial temperature of the gas, we can use Charles's Law and the formula V1/T1 = V2/T2. By substituting the known values and solving for T1, we find that the initial temperature of the gas was 86.67 °C.

Step-by-step explanation:

The question is asking for the temperature of a gas before it was heated. To find the initial temperature, we can use the formula for Charles's Law, which states that the volume of a gas is directly proportional to its temperature at constant pressure. In this case, the volume of the gas changed from 250 mL to 375 mL when heated to 130 °C. So, we need to find the initial temperature that corresponds to a volume of 250 mL.

Using the formula V1/T1 = V2/T2, where V1 = initial volume, T1 = initial temperature, V2 = final volume, and T2 = final temperature, we can substitute the known values and solve for T1.

V1 = 250 mL, T2 = 130 °C, and V2 = 375 mL. Plugging these values into the formula, we get:

250 mL/T1 = 375 mL/130 °C

Next, we can cross-multiply and solve for T1:

250 mL * 130 °C = 375 mL * T1

T1 = (250 mL * 130 °C) / 375 mL

T1 = 86.67 °C

Therefore, the temperature of the gas before it was heated was 86.67 °C.

User Thomas Reynaud
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