Question

The separation distance in B is ____ times greater than in A, the force of attraction is _______ than A.

A. Two, two times greater

B. Two, four times smaller

C. Two, two times smaller

D. Two, four times greater

Answer 1

The correct answer is B, indicating that if the separation distance in B is two times greater than in A, the force of attraction is four times smaller.

Step-by-step explanation:

The question pertains to the concept of electrostatic force as described by Coulomb's Law, which states that the force between two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

If the separation distance in B is two times greater than in A, according to Coulomb's Law, the force of attraction would not be twice greater or twice smaller but would be inversely proportional to the square of the separation.

Therefore, if the separation is doubled, the force becomes four times smaller (the square of 2 is 4). So, the correct answer is B. Two, four times smaller.