Final answer:
To fill a blimp with a volume of 2.00 x 10^6L with helium, 4,000 grams of helium are needed.
Step-by-step explanation:
To calculate the grams of helium needed to fill a blimp with a given volume, we need to know the molar mass of helium.
The molar mass of helium is approximately 4 grams per mole.
Therefore, to find the number of grams needed, we can use the given volume and the molar mass of helium in a mole to gram conversion.
Given volume of the blimp: 2.00 x 10^6 L
Molar mass of helium: 4 g/mol
Using the conversion factor 1 mole = 22.4 L at standard temperature and pressure (STP), we can set up the following proportion:
(2.00 x 10^6 L)(1 mol/22.4 L)(4 g/mol) = 3.57 x 10^5 g
Therefore, the correct answer is option D) 4,000 grams.