Question

A gas takes up a volume of 17 liters, has a pressure of 1748mmHg, and a temperature of 299K. If I raise the volume to 25 liters and lower the pressure to 1140mmHg, what is the new temperature of the gas?

A) 349K
B) 216K
C) 274K
D) 439K

Answer 1

Using the combined gas law and substituting the known values, we can solve for the new temperature of the gas, which is found to be 274K.

Step-by-step explanation:

To find the new temperature of the gas after changing the volume and pressure, we can use the combined gas law which states that the ratio of the product of pressure and volume to the temperature of a system remains constant for a given mass of gas.

The combined gas law is given by: (P1 * V1) / T1 = (P2 * V2) / T2 where P1 and V1 are the initial pressure and volume, T1 is the initial temperature, P2 and V2 are the final pressure and volume, and T2 is the final temperature.

Inserting the values into the combined gas law formula gives: (1748 mmHg * 17 L) / 299 K = (1140 mmHg * 25 L) / T2

After solving for T2, we get that the new temperature of the gas is 274K, which corresponds to option C.