Question

-7+2i/3-6i It’s operations with complex numbers is how to solve it. The answer is not -11-4/15 ok I need another answer

Answer 1

`\displaystyle\\Answer: (-11-12i)/(15)`

Explanation:

`\displaystyle\\(-7+2i)/(3-6i)=\\\\((-7+2i)(3+6i))/((3-6i)(3+6i))=\\\\ (-21-42i+6i+12i^2)/(3^2-(6i)^2) =\\\\(-21-36i-12)/(9+36)=\\\\(-33-36i)/(45) =\\\\(3(-11-12i))/(3(15)) =\\\\(-11-12i)/(15)`

Answer 2

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