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Use completing the square to find the equation of the circle. x²+y²-6x+10y-2=0 ?

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Final answer:

The equation of the circle derived using completing the square is (x - 3)² + (y + 5)² = 36, where the center of the circle is at (3,-5) with a radius of 6 units.

Step-by-step explanation:

To find the equation of the circle using completing the square, we need to rearrange the given equation x²+y²-6x+10y-2=0 and express it in the standard form of a circle's equation, which is (x-h)²+(y-k)²=r², where (h,k) is the center of the circle and r is its radius.

First, organize the x and y terms:

x² - 6x + y² + 10y = 2

Group the x terms and y terms:(x² - 6x) + (y² + 10y) = 2

Complete the square for x:

(x - 3)² = x² - 6x + 9

Complete the square for y:

(y + 5)² = y² + 10y + 25

Add these constants inside the equation balancing by adding the same amount to the other side of the equation:

(x - 3)² + (y + 5)² = 2 + 9 + 25

Simplify:

(x - 3)² + (y + 5)² = 36

The equation of the circle is now in standard form, where the center is (3,-5) and the radius is 6 units.

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