Question

Solve the system of equations

4x+ 3y+ 6e -3
6x+ 3y+ éz - 3
a (*-1, y 0,zm-1)
b. (x--l, y- 2, z m 1)
e. (0.y 1,z-0
d. (a2 y1,

Answer 1

the correct option that satisfies the given system of equations is: (x = 0, y = 1, z = 0).

The answer is option ⇒e

Step-by-step explanation:

To solve the given system of equations, we need to find the values of x, y, and z that satisfy both equations (1) and (2). We can do this by substituting the values from each option into the equations and checking if the result is equal to 0.

Let's go through each option and see if they satisfy both equations:

a. (x = -1, y = 0, z = -1):

Plugging in these values into equations (1) and (2), we get:

• 4(-1) + 3(0) + 6(-1) - 3 = -4 - 3 - 6 - 3 = -16 (not equal to 0)
• 6(-1) + 3(0) + é(-1) - 3 = -6 - 3 + é - 3 = -12 + é (not equal to 0)

Option a does not satisfy both equations.

b. (x = -1, y = 2, z = 1):

Plugging in these values into equations (1) and (2), we get:

• 4(-1) + 3(2) + 6(1) - 3 = -4 + 6 + 6 - 3 = 5 (not equal to 0)
• 6(-1) + 3(2) + é(1) - 3 = -6 + 6 + é - 3 = -3 + é (not equal to 0)

Option b does not satisfy both equations.

e. (x = 0, y = 1, z = 0):

Plugging in these values into equations (1) and (2), we get:

• 4(0) + 3(1) + 6(0) - 3 = 3 - 3 = 0 (satisfies equation (1))
• 6(0) + 3(1) + é(0) - 3 = 3 - 3 = 0 (satisfies equation (2))

Option e satisfies both equations.

d. (a = 2, y = 1, z = 2):

This option is incomplete as it does not provide a value for x. Therefore, we cannot determine if it satisfies both equations.

Based on our calculations, the correct option that satisfies the given system of equations is option c: (x = 0, y = 1, z = 0).

The answer is option ⇒e