Question

A big ship drops its anchor.

E(t)=−2.4t+75
How far does the anchor drop every 5 seconds?

Answer 1

To find out how far the anchor drops every 5 seconds, calculate the change in depth from the initial position to the position at 5 seconds using the given equation E(t) = -2.4t + 75. The anchor drops 12 meters every 5 seconds.

Step-by-step explanation:

The equation E(t) = -2.4t + 75 represents the depth of the anchor in meters at any given time t in seconds. To determine how far the anchor drops every 5 seconds, we evaluate the change in E(t) from t = 0 to t = 5 seconds.

Initially, at t = 0, E(0) = -2.4(0) + 75 = 75 meters. After 5 seconds, at t = 5, E(5) = -2.4(5) + 75 = -12 + 75 = 63 meters.

The change in depth is 75 meters - 63 meters = 12 meters. Therefore, the anchor drops 12 meters every 5 seconds.