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Two pools are being filled with water. To start, the first pool contains 707 liters of water and the second pool is empty. Water is being added to the first pool at a rate of 18.5 liters per minute. Water is being added to the second pool at a rate of 43.75 liters per minute.

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Final answer:

To fill a private swimming pool of 80,000 liters, it would take about 1,333.33 minutes or roughly 22.22 hours using a garden hose delivering 60 liters per minute. If you could divert a river flowing at 5000 m³/s into the pool, it would fill in just 0.016 seconds.

Step-by-step explanation:

The question involves calculating the time it would take to fill swimming pools with water at different rates. We can solve a question 9(a) by dividing the pool capacity by the rate at which water is delivered. For a capacity of 80,000 liters and a hose delivering 60 liters per minute, the time can be calculated as follows:

Time = Pool Capacity ÷ Flow Rate

= 80,000 L ÷ 60 L/min

= 1,333.33 minutes

This estimate tells us it would take approximately 1,333.33 minutes to fill the swimming pool using a garden hose. To convert this into hours, we divide by 60:

1,333.33 minutes ÷ 60 minutes/hour = 22.22 hours

For question 9(b), we convert the river flow from cubic meters per second to liters per second by multiplying by 1,000 (since 1 m³ = 1,000 L):

River Flow Rate = 5000 m³/s × 1,000 L/m³

= 5,000,000 L/s

Then we use this rate to calculate the filling time for the swimming pool:

Time = Pool Capacity ÷ River Flow Rate

= 80,000 L ÷ 5,000,000 L/s

= 0.016 seconds

Thus, it would take an exceptionally rapid 0.016 seconds to fill the pool if you could divert a moderate-sized river into it.

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