Question

If 238 J of heat is absorbed by a sample of metal with a mass of 40.7 g, and it raises the temperature from 20.0°C to 32.4°C, what is the specific heat capacity of the metal?

A. 2.34 J/g°C
B. 72.51 J/g°C
C. 781.12 J/g°C
D. 0.472 J/g°C

Answer 1

The specific heat capacity of the metal is approximately 0.472 J/g°C.

Step-by-step explanation:

The specific heat capacity of a metal can be determined using the formula:

Heat absorbed = mass x specific heat capacity x temperature change

Given that the mass of the metal is 40.7 g, the heat absorbed is 238 J, and the temperature change is 32.4°C - 20.0°C = 12.4°C, we can substitute these values into the formula to find the specific heat capacity:

238 J = 40.7 g x specific heat capacity x 12.4°C

Solving for the specific heat capacity, we find that it is approximately 0.472 J/g°C.