Question

A container has water at its triple point so that the solid, liquid, and gas can all exist at the same time. The container has a total of 6.9 x 10^21 mol of water molecules. If 2.4 x 10^20 mol of those are in the gas form (about 1.5 L) and the rest are in the liquid phase, how many moles of water molecules are there in the liquid?

A. 6.66 x 10^21 mol
B. 4.5 x 10^21 mol
C. 4.5 x 10^20 mol
D. 6.66 x 10^20 mol

Answer 1

The number of moles of water molecules in the liquid phase can be found by subtracting the number of moles of water molecules in the gas phase from the total number of moles of water molecules.

Step-by-step explanation:

To determine the number of moles of water molecules in the liquid phase, we need to subtract the number of moles of water molecules in the gas phase from the total number of moles of water molecules in the container. The total number of moles of water molecules in the container is given as 6.9 x 10^21 mol. The number of moles of water molecules in the gas phase is given as 2.4 x 10^20 mol. Therefore, the number of moles of water molecules in the liquid phase is:

6.9 x 10^21 mol - 2.4 x 10^20 mol = 6.66 x 10^21 mol.

So, the correct answer is A. 6.66 x 10^21 mol.