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How much will the temperature change when a 257-gram piece of iron absorbs 2551.8 joules of energy? (The specific heat of iron is 0.129 J/g °C)

A) 20°C
B) 18.9°C
C) 30°C
D) 19.8°C

1 Answer

4 votes

Final answer:

The temperature change when a 257-gram piece of iron absorbs 2551.8 joules of energy, using the specific heat of iron and the heat energy formula, is calculated to be approximately 76.5°C. However, this answer is not among the provided choices, indicating a possible error in the question or answer choices.

Step-by-step explanation:

To determine how much the temperature will change when a 257-gram piece of iron absorbs 2551.8 joules of energy, we can use the formula q = m × c × ΔT, where q is the heat energy absorbed, m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature. We rearrange the equation to solve for ΔT: ΔT = q / (m × c).

Substituting the given values: ΔT = 2551.8 J / (257 g × 0.129 J/g°C) equals approximately 76.5°C.

However, this doesn't match any of the provided answer choices. Considering a possible typo or miscalculation in the question, let's cross-check with the specific heat value and calculation provided:

ΔT = q / (m × c) = 2551.8 J / (257 g × 0.129 J/g°C) = 76.5°C (This seems to be an error in the provided choices given that none match 76.5°C.)

Therefore, the correct answer isn't listed among the options A) 20°C, B) 18.9°C, C) 30°C, or D) 19.8°C.

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