Final answer:
The total amount of heat energy released when 250 grams of water cools from 50°C to 25°C is calculated to be 26,150 J, which does not match any of the provided options (A-D). There may be a mistake in the question or options.
Step-by-step explanation:
The calculation of the total amount of heat energy released when a certain mass of water cools from one temperature to another can be found using the specific heat formula: Q = mcΔT, where Q is the heat energy, m is the mass, c is the specific heat capacity (for water, it is 4.184 J/g°C), and ΔT is the change in temperature.
For 250 grams of water cooling from 50°C to 25°C, the change in temperature (ΔT) is 25°C (50°C - 25°C). Thus, using the mass (m) of 250 g and the specific heat capacity (c) of water, we calculate the heat energy (Q) released: Q = (250 g)(4.184 J/g°C)(25°C).
Plugging in the numbers: Q = 250 g × 4.184 J/g°C × 25°C = 26,150 J.
However, none of the given options (A) 12.5 J, (B) 250 J, (C) 375 J, (D) 500 J matches the calculated value, indicating a potential mistake in the question or the options provided. The correct energy released is significantly higher than any of the options.