Question

The time a male bungee jumper is freely falling is 1.5 seconds. What is the velocity of the jumper at the end of 1.5 seconds? And how far does he fall?

Answer 1

The velocity of the male bungee jumper at the end of 1.5 seconds is 14.7 m/s, and he falls approximately 11.025 meters during that time.

Step-by-step explanation:

To determine the velocity of the jumper at the end of 1.5 seconds, we can use the formula for velocity in free fall, which is v = gt, where g is the acceleration due to gravity (9.8 m/s² on Earth) and t is the time in seconds. The velocity (v) of the male bungee jumper after 1.5 seconds is thus:

v = 9.8 m/s² × 1.5 s = 14.7 m/s

Next, to calculate how far the jumper falls in that time, we use the formula for displacement in free fall, which is s = (1/2)gt². So, the distance (s) he falls is:

s = (1/2) × 9.8 m/s² × (1.5 s)² = 11.025 m

Therefore, the velocity of the jumper at the end of 1.5 seconds is 14.7 m/s and the distance he falls is approximately 11.025 meters.