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In Δbcd, the line segment bd is extended through point d to point e. Given that m∠bcd = (3x + 11)°, m∠dbc = (2x + 16)°, and m∠cde = (8x - 15)°, what is the value of x?

User Hai Nguyen
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1 Answer

4 votes

Final answer:

By applying the exterior angle theorem to the given angles in Δbcd, we determine the value of x to be 14.

Step-by-step explanation:

To find the value of x in Δbcd where the line segment bd is extended through point d to point e, we can use the properties of exterior angles in a triangle. The exterior angle theorem states that the measure of an exterior angle is equal to the sum of the measures of the two non-adjacent interior angles.

Given:
m∠bcd = (3x + 11)°
m∠dbc = (2x + 16)°
m∠cde = (8x - 15)°

According to the exterior angle theorem:
m∠cde = m∠bcd + m∠dbc
(8x - 15)° = (3x + 11)° + (2x + 16)°

Combine like terms:
(8x - 15)° = (5x + 27)°
8x - 15 = 5x + 27

Solve for x:
3x = 42
x = 14

Therefore, the value of x is 14.

User Mspir
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