Final answer:
The vertices of Δa'b'c' are located at (-9, 9), (-3, 6), and (0, 12) after being reflected over the y-axis and dilated by a scale factor of 3 about the origin.
Step-by-step explanation:
To find the vertices of the reflected and dilated triangle, we need to apply both transformations to each vertex of the original triangle.
First, reflect each vertex over the y-axis. This means changing the sign of the x-coordinate for each vertex.
- For vertex A, (3, 3), the reflected vertex is (-3, 3).
- For vertex B, (1, 2), the reflected vertex is (-1, 2).
- For vertex C, (0, 4), the reflected vertex is (0, 4).
Next, dilate each reflected vertex about the origin by a scale factor of 3. This means multiplying both the x-coordinate and y-coordinate by 3.
- For vertex A', (-3, 3), the dilated vertex is (-9, 9).
- For vertex B', (-1, 2), the dilated vertex is (-3, 6).
- For vertex C', (0, 4), the dilated vertex is (0, 12).
Therefore, the vertices of Δa'b'c' are located at (-9, 9), (-3, 6), and (0, 12) (Option 3).