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A rocket with a mass of 2000 kg is launched vertically upwards from the ground. The thrust of the rocket engine is 5000 N. When the rocket has reached an altitude of 120 m, how hard does the floor push on the power supply? Neglect the air resistance.

User Prikha
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Final answer:

The force with which the floor pushes on the power supply of the rocket is equal to the weight of the rocket, which can be calculated by multiplying the mass of the rocket by the acceleration due to gravity.

Step-by-step explanation:

The floor pushes on the power supply of the rocket with a force equal in magnitude but opposite in direction to the weight of the rocket. This force is known as the normal force. When the rocket is launched vertically upwards, the normal force is equal to the weight of the rocket. Since the weight of the rocket is given by the equation weight = mass x acceleration due to gravity, we can calculate it by multiplying the mass of the rocket (2000 kg) by the acceleration due to gravity (9.8 m/s^2).

Therefore, the force with which the floor pushes on the power supply is 2000 kg x 9.8 m/s^2 = 19,600 N.

User KaseOga
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