Final answer:
In the reaction between aqueous H₂SO₄ and NaOH, all species are dissociated except for water (H₂O), which remains undissociated as a liquid. The balanced equation reflecting this is H₂SO₄(aq) + 2NaOH(aq) → Na₂SO₄(aq) + 2H₂O(l).
Step-by-step explanation:
When aqueous H₂SO₄ (sulfuric acid) and NaOH (sodium hydroxide) react, the products formed are water (H₂O) and sodium sulfate (Na₂SO₄). Because sulfuric acid is a strong acid and sodium hydroxide is a strong base, both of these substances fully dissociate into ions when dissolved in water. Sulfuric acid (H₂SO₄) disassociates into 2H+ ions and SO₄²⁻ ion, and sodium hydroxide disassociates into Na+ and OH⁻ ions.
The balanced chemical equation for this reaction is:
H₂SO₄ (aq) + 2NaOH(aq) → Na₂SO₄ (aq) + 2H₂O(l)
All the species in this equation are dissociated except for water (H₂O), which remains as a molecular compound in the liquid state. Therefore, the only undissociated species in this reaction is water.
The mole ratio of H₂SO₄ to NaOH is 1:2, which means that it takes twice as many moles of NaOH to fully neutralize H₂SO₄. This is evident from the balanced equation where 1 mole of H₂SO₄ reacts with 2 moles of NaOH.