The equation y=−x+ 3/2, the graph is a straight line with a slope of -1 and a y-intercept of 3/2 .
To graph the linear equation y=−x+ 3/2 using the slope and intercept, you can follow these steps:
The given equation is in slope-intercept form
y=mx+b,
where
m is the slope and b is the y-intercept.
Identify the Slope (m):
In the equation
y=−x+ 3/2 , the coefficient of x is -1. Therefore, the slope (m) is -1.
Identify the Y-Intercept (b):
The y-intercept is the constant term in the equation, which is 3/2.
So, the y-intercept (b) is 3/2 .
Plot the Y-Intercept:
Plot the point (0,3/2) on the coordinate plane. This is where the line crosses the y-axis.
Use the Slope to Find Another Point:
Since the slope (m) is -1, you can use this to find another point. The slope is the "rise over run," so for every 1 unit you move to the right (run), you go down 1 unit (rise). Starting from the y-intercept, move 1 unit to the right and 1 unit down to find another point.
Draw the Line:
Connect the two points you plotted with a straight line. Since the equation is linear, the line extends infinitely in both directions.
So, for the equation y=−x+ 3/2, the graph is a straight line with a slope of -1 and a y-intercept of 3/2 .
Question
How do you graph y=-x+3/2 using the slope and intercept?