The solution is x = -6 and y = -4.
To solve the system of equations 8x - 8y = -16 and -2x + 6y = -12, we can use the method of combination.
In order to eliminate one variable, let's multiply the first equation by 3 and the second equation by 4.
This will give us 24x - 24y = -48 and -8x + 24y = -48.
Now, add the two equations together to eliminate the variable 'y'.
The resulting equation is 16x = -96.
Divide both sides by 16 to solve for 'x', giving us x = -6.
Now that we have the value of 'x', substitute it back into one of the original equations.
Let's use the first equation: 8x - 8y = -16. Substitute the value of 'x' to get 8(-6) - 8y = -16.
Simplify to get -48 - 8y = -16. Add 48 to both sides to isolate the variable 'y', giving us -8y = 32.
Divide both sides by -8 to solve for 'y', giving us y = -4.
Therefore, the solution to the system of equations is x = -6 and y = -4.
The probable question may be:
Solve the system of equations 8x - 8y = -16 and -2x+6y= -12 by combining the equations.
(8x -8y =-16) (-2x+6y=-12)
8x -8y = -16 -2x+6y=-12