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How do you write an equation of a line whose y-intercept is 3/5 and slope is -9/2 in standard form?

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Final answer:

To write the equation of a line with a y-intercept of 3/5 and a slope of -9/2 in standard form, substitute the given values into the equation y = mx + b. To convert the equation to standard form, eliminate all fractional coefficients by multiplying the equation by a suitable factor.

Step-by-step explanation:

To write the equation of a line with a y-intercept of 3/5 and a slope of -9/2 in standard form, we can use the formula y = mx + b, where m is the slope and b is the y-intercept.

Substituting the given values, we get y = (-9/2)x + 3/5.

To convert the equation to standard form, we need to eliminate all fractional coefficients. To do this, we can multiply the entire equation by 10, resulting in 10y = -45x + 6.

The equation of the line in standard form is therefore 45x + 10y = 6.

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