The fraction (3x-2)/x³(x²+4) can be written as: (3x-2)/x * 1/x * 1/x * 1/(x²+4)
To divide the fraction (3x-2)/x³(x²+4) into four fractions, we need to break it down into simpler fractions.
Here's how to do it:
Factorize the denominator: x³(x²+4) = x³ * (x²+4)
Write the original fraction as: (3x-2)/(x³ * (x²+4))
Break it down into four fractions by separating the numerator and denominator: [3x / (x³ * (x²+4))] - [2 / (x³ * (x²+4))]
Simplify the fractions if possible by canceling out common factors between the numerator and denominator.
So, the fraction (3x-2)/x³(x²+4) can be written as: (3x-2)/x * 1/x * 1/x * 1/(x²+4)