Final answer:
To calculate the concentration of all ions present in 5.00 g of NH4Cl in 900.0 mL of solution, convert the mass of NH4Cl to moles, calculate the volume of the solution in liters, and divide the number of moles by the volume of the solution.
Step-by-step explanation:
To calculate the concentration of all ions present in 5.00 g of NH4Cl in 900.0 mL of solution, we first need to convert the mass of NH4Cl to moles. The molar mass of NH4Cl is 53.50 g/mol, so the number of moles is 5.00 g NH4Cl / 53.50 g/mol = 0.0933 mol NH4Cl. Next, we need to calculate the volume of the solution in liters. 900.0 mL is equivalent to 0.9000 L. Finally, we can calculate the molarity (concentration) of the NH4Cl by dividing the number of moles by the volume of the solution: 0.0933 mol NH4Cl / 0.9000 L = 0.104 M.