Question

Jina, Boris, and Goran served a total of 110 orders Monday at the school cafeteria. Goran served 3 times as many orders as Jina. Jina served 10 more orders than Boris. How many orders did they each serve?

Answer 1

Boris served 14 orders, Jina served 24 orders, and Goran served 72 orders, which all add up to the total of 110 orders served at the school cafeteria on Monday.

Step-by-step explanation:

To solve the problem of how many orders Jina, Boris, and Goran served, we can use algebra.

Let's denote the number of orders served by Boris as B.

According to the problem, Jina served 10 more orders than Boris, which can be expressed as J = B + 10.

Goran served 3 times as many orders as Jina, written as G = 3J.

The total number of orders served by all three is 110, so we have the equation B + J + G = 110.

Substituting J and G in terms of B, we get:

B + (B + 10) + 3(B + 10) = 110

Solving for B:

1. Combine like terms: B + B + 10 + 3B + 30 = 110
2. Simplify: 5B + 40 = 110
3. Subtract 40 from both sides: 5B = 70
4. Divide by 5 to find B: B = 14

Now we can find J and G:

J = B + 10

= 14 + 10

24

G = 3J

= 3 × 24

= 72

So Boris served 14 orders, Jina served 24 orders, and Goran served 72 orders.