Question

A force f = fx i + fy j acts on a particle that undergoes a displacement of s = sx i + sy j where fx = 9 n, fy = -3 n, sx = 3 m, and sy = 3 m. Find the work done by the force on the particle. Answer in units of J.

Answer 1

The work done by the force on the particle is 18 J.

Step-by-step explanation:

To find the work done by a force on a particle, we can use the formula:

Work (W) = force (F) dot displacement (s)

Given: fx = 9 N, fy = -3 N, sx = 3 m, sy = 3 m

First, calculate the dot product of the force and displacement vectors:

W = (fx)(sx) + (fy)(sy)

Substituting the given values:

W = (9 N)(3 m) + (-3 N)(3 m)

W = 27 J + (-9 J)

W = 18 J

Therefore, the work done by the force on the particle is 18 J.