Final answer:
The period of a pendulum made of a uniform rod with a length of 80.0 cm swinging in simple harmonic motion on Earth is approximately 1.79 seconds.
Step-by-step explanation:
The question pertains to calculating the period of a pendulum made of a uniform rod on Earth. A pendulum undergoing simple harmonic motion (SHM) has a period given by the formula T = 2π√(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity which is approximately 9.81 m/s2 on Earth's surface. The length given is 80.0 cm, which we convert to meters (0.80 m) to use in the formula. Plugging these values into the formula yields:
T = 2π√(0.80 m / 9.81 m/s2) = 2π√(0.08155 s2) ≈ 1.79 s.
Therefore, the period of the pendulum is approximately 1.79 seconds.