Question

A glass optical fiber in a communications system has a diameter of 10.5 μm. If the glass has a tensile strength of 52.8*10⁶ N/m², what is the maximum tension in MN that this fiber could support without breaking?

Answer 1

To calculate the maximum tension that a glass optical fiber can support without breaking, you need to calculate the maximum stress using the formula Maximum Stress = Maximum Tension / Cross-sectional Area. Then, divide the maximum stress by 10^6 to find the maximum tension in MN.

Step-by-step explanation:

To calculate the maximum tension that a glass optical fiber can support without breaking, we first need to calculate the maximum stress.

The maximum stress is given by the formula:

Maximum Stress = Maximum Tension / Cross-sectional Area

The cross-sectional area of the fiber can be calculated using the formula:

Area = π * (Radius)^2

Given that the diameter of the fiber is 10.5 μm, we can calculate the radius by dividing the diameter by 2:

Radius = 10.5 μm / 2 = 5.25 μm = 5.25 × 10^-6 m

Substituting the values into the area formula:

Area = π * (5.25 × 10^-6)^2

Now we can calculate the maximum stress:

Maximum Stress = (52.8 × 10^6 N/m²) / Area

Finally, to calculate the maximum tension in MN, we divide the maximum stress by 10^6:

Maximum Tension (MN) = Maximum Stress / 10^6