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A chemist prepares a solution of iron(iii) bromide febr3 by weighing out 50.27g of iron(iii) bromide into a volumetric flask and filling the flask to the mark with water. Calculate the concentration in g/dL of the chemist's iron(iii) bromide solution. Be sure your answer has the correct number of significant digits.

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Final answer:

The concentration of the chemist's iron(III) bromide solution is 5.027 g/dL, assuming the solution was prepared in a standard 1 L volumetric flask.

Step-by-step explanation:

To calculate the concentration in g/dL of the chemist's iron(III) bromide solution, we should first identify the total volume of the solution in deciliters (dL). Typically, volumetric flasks come in standard sizes, but since the specific volume is not mentioned in the question, we'll assume the commonly used 1 L (liter) flask for such preparations. Since 1 L is equivalent to 10 dL, the flask volume is 10 dL.

With the mass of iron(III) bromide (FeBr3) given as 50.27 g, the concentration can be calculated by dividing the mass of the compound by the volume of the solution:

Concentration (g/dL) = Mass of solute (g) / Volume of solution (dL)

Concentration (g/dL) = 50.27 g / 10 dL = 5.027 g/dL

The concentration of the solution is 5.027 g/dL, and this should be reported with four significant digits because the mass of iron(III) bromide is given to four significant figures and assuming the volume of the flask is measured precisely.

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