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A 1500 kg car traveling at a speed of 19 m/s skids to a halt on wet concrete where μk = 0.40. What is the stopping distance of the car?

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Final answer:

The stopping distance of the car is 44.60 meters.

Step-by-step explanation:

To calculate the stopping distance of the car, we can use the equation:

d = v^2 / (2 * a)

where d is the stopping distance, v is the initial velocity, and a is the acceleration.

Given that the car is traveling at a speed of 19 m/s and the coefficient of kinetic friction, μk, is 0.40, we can determine the acceleration using the equation:

a = μk * g

where g is the acceleration due to gravity, approximately 9.81 m/s^2.

By substituting the values into the equations and solving for d, we find:

d = (19^2) / (2 * (0.40 * 9.81)) = 44.60 meters

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