92,469 views
12 votes
12 votes
How do i solve for this

How do i solve for this-example-1
User Harry Wang
by
2.5k points

1 Answer

11 votes
11 votes

Answer:

x = -4

Explanation:


\frac{ \sqrt[3]{6x} }{ \sqrt[3]{2x + 5} } = 2


{( \frac{ \sqrt[3]{6x} }{ \sqrt[3]{2x + 5} } )}^(3) = {2}^(3)


(6x)/(2x + 5) = 8


6x = 8(2x + 5)


6x = 16x + 40


- 10x = 40


x = - 4


\frac{ \sqrt[3]{6( - 4)} }{ \sqrt[3]{2( - 4) + 5} } = 2


\frac{ \sqrt[3]{ - 24} }{ \sqrt[3]{ - 3} } = 2


\sqrt[3]{ ( - 24)/( - 3) } = 2


\sqrt[3]{8} = 2

User Byrdr
by
3.1k points