Question

They decide to let the person more likely to attend both events have the parking pass. Assuming that attendance at one activity is independent of attendance at the other, who is more likely to attend both activities?

1) The person who attends the first activity
2) The person who attends the second activity
3) Both are equally likely to attend both activities
4) Cannot be determined

Answer 1

To determine who is more likely to attend both activities, compare the probabilities of attending each activity for both persons. The person who attends the first activity is more likely to attend both activities if their attendance probability is higher than the person attending the second activity.

Step-by-step explanation:

To determine who is more likely to attend both activities, we need to consider the probability of attendance for each person. Since attendance at one activity is independent of attendance at the other, the probability of attending both activities is the product of the probabilities of attending each activity. Let's say person A attends the first activity with a probability of P(A) and person B attends the second activity with a probability of P(B).

The probability of both persons attending both activities can be calculated as P(A) * P(B).

Therefore, the person who attends the first activity is more likely to attend both activities if P(A) > P(B), and vice versa.

Both persons are equally likely to attend both activities if P(A) = P(B).