Final answer:
The molarity of a solution containing 6.3g of NaOH in 550ml is calculated by first converting the mass of NaOH to moles, then the volume to liters, and finally dividing the moles by the liters, which results in approximately 0.2864 M.
Step-by-step explanation:
Calculating the Molarity of NaOH Solution
To calculate the molarity of a solution containing 6.3g of NaOH in 550ml of solution, we first need to convert grams of NaOH to moles. The molar mass of NaOH is approximately 40.00 g/mol. Therefore:
Moles of NaOH = mass (g) / molar mass (g/mol) = 6.3 g / 40.00 g/mol = 0.1575 moles NaOH
Next, we convert the volume of the solution from mL to L, which is necessary for the molarity calculation:
Volume of solution = 550 mL = 0.550 L
The molarity (M) is defined as the number of moles of solute (NaOH in this case) divided by the volume of the solution in liters:
Molarity (M) = moles of solute / volume of solution in L = 0.1575 moles / 0.550 L
Therefore, the molarity of the NaOH solution is approximately:
M = 0.2864 M