Question

A liquid flows in a tube by a constant rate 0.02m³/min, if the section area of the tube is 3cm², what is the speed of the liquid through the tube ?​

Answer 1

The speed of the liquid through the tube is 1.11 m/s.

Step-by-step explanation:

The speed of the liquid through the tube can be calculated using the equation:

speed = flow rate / cross-sectional area

Given that the flow rate is 0.02 m³/min and the cross-sectional area of the tube is 3 cm², we first convert the flow rate to m³/s:

0.02 m³/min = 0.02/60 m³/s = 0.000333 m³/s

Next, we convert the cross-sectional area from cm² to m²:

3 cm² = 3/10000 m² = 0.0003 m²

Now we can calculate the speed:

speed = 0.000333 m³/s / 0.0003 m² = 1.11 m/s

Therefore, the speed of the liquid through the tube is 1.11 m/s.